(133-6n)=(n+8)+(4n-18)

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Solution for (133-6n)=(n+8)+(4n-18) equation: 



(133-6n)=(n+8)+(4n-18)

We move all terms to the left:

(133-6n)-((n+8)+(4n-18))=0

We add all the numbers together, and all the variables

(-6n+133)-((n+8)+(4n-18))=0

We get rid of parentheses

-6n-((n+8)+(4n-18))+133=0



We calculate terms in parentheses: -((n+8)+(4n-18)), so:

(n+8)+(4n-18)

We get rid of parentheses

n+4n+8-18

We add all the numbers together, and all the variables

5n-10

Back to the equation:

-(5n-10)



We get rid of parentheses

-6n-5n+10+133=0

We add all the numbers together, and all the variables

-11n+143=0

We move all terms containing n to the left, all other terms to the right

-11n=-143

n=-143/-11

n=+13

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