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Simplifying (13b + 8) * x(5b + -15) = 0 Reorder the terms: (8 + 13b) * x(5b + -15) = 0 Reorder the terms: (8 + 13b) * x(-15 + 5b) = 0 Reorder the terms for easier multiplication: x(8 + 13b)(-15 + 5b) = 0 Multiply (8 + 13b) * (-15 + 5b) x(8(-15 + 5b) + 13b * (-15 + 5b)) = 0 x((-15 * 8 + 5b * 8) + 13b * (-15 + 5b)) = 0 x((-120 + 40b) + 13b * (-15 + 5b)) = 0 x(-120 + 40b + (-15 * 13b + 5b * 13b)) = 0 x(-120 + 40b + (-195b + 65b2)) = 0 Combine like terms: 40b + -195b = -155b x(-120 + -155b + 65b2) = 0 (-120 * x + -155b * x + 65b2 * x) = 0 Reorder the terms: (-155bx + 65b2x + -120x) = 0 (-155bx + 65b2x + -120x) = 0 Solving -155bx + 65b2x + -120x = 0 Solving for variable 'b'. Factor out the Greatest Common Factor (GCF), '5x'. 5x(-31b + 13b2 + -24) = 0 Factor a trinomial. 5x((b + -3)(13b + 8)) = 0 Ignore the factor 5.Subproblem 1
Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing b to the left, all other terms to the right. Add '-1x' to each side of the equation. x + -1x = 0 + -1x Remove the zero: 0 = -1x Simplifying 0 = -1x The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.Subproblem 2
Set the factor '(b + -3)' equal to zero and attempt to solve: Simplifying b + -3 = 0 Reorder the terms: -3 + b = 0 Solving -3 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + b = 0 + 3 Combine like terms: -3 + 3 = 0 0 + b = 0 + 3 b = 0 + 3 Combine like terms: 0 + 3 = 3 b = 3 Simplifying b = 3Subproblem 3
Set the factor '(13b + 8)' equal to zero and attempt to solve: Simplifying 13b + 8 = 0 Reorder the terms: 8 + 13b = 0 Solving 8 + 13b = 0 Move all terms containing b to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + 13b = 0 + -8 Combine like terms: 8 + -8 = 0 0 + 13b = 0 + -8 13b = 0 + -8 Combine like terms: 0 + -8 = -8 13b = -8 Divide each side by '13'. b = -0.6153846154 Simplifying b = -0.6153846154Solution
b = {3, -0.6153846154}
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