(13b-7)-3(4b+2)=-6

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Solution for (13b-7)-3(4b+2)=-6 equation: 



(13b-7)-3(4b+2)=-6

We move all terms to the left:

(13b-7)-3(4b+2)-(-6)=0

We add all the numbers together, and all the variables

(13b-7)-3(4b+2)+6=0

We multiply parentheses

(13b-7)-12b-6+6=0

We get rid of parentheses

13b-12b-7-6+6=0

We add all the numbers together, and all the variables

b-7=0

We move all terms containing b to the left, all other terms to the right

b=7

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