(13b-7)-3(4b+2)=-6

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Solution for (13b-7)-3(4b+2)=-6 equation:



(13b-7)-3(4b+2)=-6
We move all terms to the left:
(13b-7)-3(4b+2)-(-6)=0
We add all the numbers together, and all the variables
(13b-7)-3(4b+2)+6=0
We multiply parentheses
(13b-7)-12b-6+6=0
We get rid of parentheses
13b-12b-7-6+6=0
We add all the numbers together, and all the variables
b-7=0
We move all terms containing b to the left, all other terms to the right
b=7

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