(13x+12)=(21x-2)

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Solution for (13x+12)=(21x-2) equation: 



(13x+12)=(21x-2)

We move all terms to the left:

(13x+12)-((21x-2))=0

We get rid of parentheses

13x-((21x-2))+12=0



We calculate terms in parentheses: -((21x-2)), so:

(21x-2)

We get rid of parentheses

21x-2

Back to the equation:

-(21x-2)



We get rid of parentheses

13x-21x+2+12=0

We add all the numbers together, and all the variables

-8x+14=0

We move all terms containing x to the left, all other terms to the right

-8x=-14

x=-14/-8

x=1+3/4

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