(13x+2)+(3x-4)=(5x-7)

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Solution for (13x+2)+(3x-4)=(5x-7) equation: 



(13x+2)+(3x-4)=(5x-7)

We move all terms to the left:

(13x+2)+(3x-4)-((5x-7))=0

We get rid of parentheses

13x+3x-((5x-7))+2-4=0



We calculate terms in parentheses: -((5x-7)), so:

(5x-7)

We get rid of parentheses

5x-7

Back to the equation:

-(5x-7)



We add all the numbers together, and all the variables

16x-(5x-7)-2=0

We get rid of parentheses

16x-5x+7-2=0

We add all the numbers together, and all the variables

11x+5=0

We move all terms containing x to the left, all other terms to the right

11x=-5

x=-5/11

x=-5/11

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