(13x+2)=(5x-7)=(3x-4)

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Solution for (13x+2)=(5x-7)=(3x-4) equation: 



(13x+2)=(5x-7)=(3x-4)

We move all terms to the left:

(13x+2)-((5x-7))=0

We get rid of parentheses

13x-((5x-7))+2=0



We calculate terms in parentheses: -((5x-7)), so:

(5x-7)

We get rid of parentheses

5x-7

Back to the equation:

-(5x-7)



We get rid of parentheses

13x-5x+7+2=0

We add all the numbers together, and all the variables

8x+9=0

We move all terms containing x to the left, all other terms to the right

8x=-9

x=-9/8

x=-1+1/8

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