(13x-2)+(10x+28)=180

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Solution for (13x-2)+(10x+28)=180 equation: 



(13x-2)+(10x+28)=180

We move all terms to the left:

(13x-2)+(10x+28)-(180)=0

We get rid of parentheses

13x+10x-2+28-180=0

We add all the numbers together, and all the variables

23x-154=0

We move all terms containing x to the left, all other terms to the right

23x=154

x=154/23

x=6+16/23

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