(13x-3)=(3x+2)+55

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Solution for (13x-3)=(3x+2)+55 equation: 



(13x-3)=(3x+2)+55

We move all terms to the left:

(13x-3)-((3x+2)+55)=0

We get rid of parentheses

13x-((3x+2)+55)-3=0



We calculate terms in parentheses: -((3x+2)+55), so:

(3x+2)+55

We get rid of parentheses

3x+2+55

We add all the numbers together, and all the variables

3x+57

Back to the equation:

-(3x+57)



We get rid of parentheses

13x-3x-57-3=0

We add all the numbers together, and all the variables

10x-60=0

We move all terms containing x to the left, all other terms to the right

10x=60

x=60/10

x=6

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