(13x-35)+(5x-19)=(13x-35)+(2x+14)

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Solution for (13x-35)+(5x-19)=(13x-35)+(2x+14) equation: 



(13x-35)+(5x-19)=(13x-35)+(2x+14)

We move all terms to the left:

(13x-35)+(5x-19)-((13x-35)+(2x+14))=0

We get rid of parentheses

13x+5x-((13x-35)+(2x+14))-35-19=0



We calculate terms in parentheses: -((13x-35)+(2x+14)), so:

(13x-35)+(2x+14)

We get rid of parentheses

13x+2x-35+14

We add all the numbers together, and all the variables

15x-21

Back to the equation:

-(15x-21)



We add all the numbers together, and all the variables

18x-(15x-21)-54=0

We get rid of parentheses

18x-15x+21-54=0

We add all the numbers together, and all the variables

3x-33=0

We move all terms containing x to the left, all other terms to the right

3x=33

x=33/3

x=11

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