(13x-35)=(5x-17)+(2x+14)

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Solution for (13x-35)=(5x-17)+(2x+14) equation: 



(13x-35)=(5x-17)+(2x+14)

We move all terms to the left:

(13x-35)-((5x-17)+(2x+14))=0

We get rid of parentheses

13x-((5x-17)+(2x+14))-35=0



We calculate terms in parentheses: -((5x-17)+(2x+14)), so:

(5x-17)+(2x+14)

We get rid of parentheses

5x+2x-17+14

We add all the numbers together, and all the variables

7x-3

Back to the equation:

-(7x-3)



We get rid of parentheses

13x-7x+3-35=0

We add all the numbers together, and all the variables

6x-32=0

We move all terms containing x to the left, all other terms to the right

6x=32

x=32/6

x=5+1/3

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