(13x-4)+(9x-31)=(13x-4)+(4x-1)

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Solution for (13x-4)+(9x-31)=(13x-4)+(4x-1) equation: 



(13x-4)+(9x-31)=(13x-4)+(4x-1)

We move all terms to the left:

(13x-4)+(9x-31)-((13x-4)+(4x-1))=0

We get rid of parentheses

13x+9x-((13x-4)+(4x-1))-4-31=0



We calculate terms in parentheses: -((13x-4)+(4x-1)), so:

(13x-4)+(4x-1)

We get rid of parentheses

13x+4x-4-1

We add all the numbers together, and all the variables

17x-5

Back to the equation:

-(17x-5)



We add all the numbers together, and all the variables

22x-(17x-5)-35=0

We get rid of parentheses

22x-17x+5-35=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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