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(13x-43)x==
We move all terms to the left:
(13x-43)x-()=0
We add all the numbers together, and all the variables
(13x-43)x=0
We multiply parentheses
13x^2-43x=0
a = 13; b = -43; c = 0;
Δ = b2-4ac
Δ = -432-4·13·0
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-43}{2*13}=\frac{0}{26} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+43}{2*13}=\frac{86}{26} =3+4/13 $
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