(14)/(x-5)+(3x+2)/x=0

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Solution for (14)/(x-5)+(3x+2)/x=0 equation: 


D( x )

x-5 = 0

x = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x = 0

x = 0

x in (-oo:0) U (0:5) U (5:+oo)

14/(x-5)+(3*x+2)/x = 0

(14*x)/(x*(x-5))+((3*x+2)*(x-5))/(x*(x-5)) = 0

(3*x+2)*(x-5)+14*x = 0

3*x^2+x-10 = 0

3*x^2+x-10 = 0

3*x^2+x-10 = 0

DELTA = 1^2-(-10*3*4)

DELTA = 121

DELTA > 0

x = (121^(1/2)-1)/(2*3) or x = (-121^(1/2)-1)/(2*3)

x = 5/3 or x = -2

(x+2)*(x-5/3) = 0

((x+2)*(x-5/3))/(x*(x-5)) = 0

((x+2)*(x-5/3))/(x*(x-5)) = 0 // * x*(x-5)

(x+2)*(x-5/3) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-5/3 )

x-5/3 = 0 // + 5/3

x = 5/3

x in { -2, 5/3 }

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