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(14+2a)+((5a-12)-(3a+4))+14+2a+(3a+4)+(5a-12)=144
We move all terms to the left:
(14+2a)+((5a-12)-(3a+4))+14+2a+(3a+4)+(5a-12)-(144)=0
We add all the numbers together, and all the variables
(2a+14)+((5a-12)-(3a+4))+2a+(3a+4)+(5a-12)+14-144=0
We add all the numbers together, and all the variables
2a+(2a+14)+((5a-12)-(3a+4))+(3a+4)+(5a-12)-130=0
We get rid of parentheses
2a+2a+((5a-12)-(3a+4))+3a+5a+14+4-12-130=0
We calculate terms in parentheses: +((5a-12)-(3a+4)), so:We add all the numbers together, and all the variables
(5a-12)-(3a+4)
We get rid of parentheses
5a-3a-12-4
We add all the numbers together, and all the variables
2a-16
Back to the equation:
+(2a-16)
12a+(2a-16)-124=0
We get rid of parentheses
12a+2a-16-124=0
We add all the numbers together, and all the variables
14a-140=0
We move all terms containing a to the left, all other terms to the right
14a=140
a=140/14
a=10
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