(14+2n)+(8n-6)=(n+34)-(21-4n)

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Solution for (14+2n)+(8n-6)=(n+34)-(21-4n) equation: 



(14+2n)+(8n-6)=(n+34)-(21-4n)

We move all terms to the left:

(14+2n)+(8n-6)-((n+34)-(21-4n))=0

We add all the numbers together, and all the variables

(2n+14)+(8n-6)-((n+34)-(-4n+21))=0

We get rid of parentheses

2n+8n-((n+34)-(-4n+21))+14-6=0



We calculate terms in parentheses: -((n+34)-(-4n+21)), so:

(n+34)-(-4n+21)

We get rid of parentheses

n+4n+34-21

We add all the numbers together, and all the variables

5n+13

Back to the equation:

-(5n+13)



We add all the numbers together, and all the variables

10n-(5n+13)+8=0

We get rid of parentheses

10n-5n-13+8=0

We add all the numbers together, and all the variables

5n-5=0

We move all terms containing n to the left, all other terms to the right

5n=5

n=5/5

n=1

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