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(14+2x)(20+2x)=832
We move all terms to the left:
(14+2x)(20+2x)-(832)=0
We add all the numbers together, and all the variables
(2x+14)(2x+20)-832=0
We multiply parentheses ..
(+4x^2+40x+28x+280)-832=0
We get rid of parentheses
4x^2+40x+28x+280-832=0
We add all the numbers together, and all the variables
4x^2+68x-552=0
a = 4; b = 68; c = -552;
Δ = b2-4ac
Δ = 682-4·4·(-552)
Δ = 13456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13456}=116$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-116}{2*4}=\frac{-184}{8} =-23 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+116}{2*4}=\frac{48}{8} =6 $
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