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(14+2x)(24+2x)=x
We move all terms to the left:
(14+2x)(24+2x)-(x)=0
We add all the numbers together, and all the variables
(2x+14)(2x+24)-x=0
We add all the numbers together, and all the variables
-1x+(2x+14)(2x+24)=0
We multiply parentheses ..
(+4x^2+48x+28x+336)-1x=0
We get rid of parentheses
4x^2+48x+28x-1x+336=0
We add all the numbers together, and all the variables
4x^2+75x+336=0
a = 4; b = 75; c = +336;
Δ = b2-4ac
Δ = 752-4·4·336
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-\sqrt{249}}{2*4}=\frac{-75-\sqrt{249}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+\sqrt{249}}{2*4}=\frac{-75+\sqrt{249}}{8} $
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