(14+2x)(30+2x)=836

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Solution for (14+2x)(30+2x)=836 equation:



(14+2x)(30+2x)=836
We move all terms to the left:
(14+2x)(30+2x)-(836)=0
We add all the numbers together, and all the variables
(2x+14)(2x+30)-836=0
We multiply parentheses ..
(+4x^2+60x+28x+420)-836=0
We get rid of parentheses
4x^2+60x+28x+420-836=0
We add all the numbers together, and all the variables
4x^2+88x-416=0
a = 4; b = 88; c = -416;
Δ = b2-4ac
Δ = 882-4·4·(-416)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-120}{2*4}=\frac{-208}{8} =-26 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+120}{2*4}=\frac{32}{8} =4 $

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