(14-2i)(7+2i)=0

Solution for (14-2i)(7+2i)=0 equation:

(14-2i)(7+2i)=0

We add all the numbers together, and all the variables

(-2i+14)(2i+7)=0

We multiply parentheses ..

(-4i^2-14i+28i+98)=0

We get rid of parentheses

-4i^2-14i+28i+98=0

We add all the numbers together, and all the variables

-4i^2+14i+98=0

a = -4; b = 14; c = +98;
Δ = b2-4ac
Δ = 142-4·(-4)·98
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-42}{2*-4}=\frac{-56}{-8}
=+7
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+42}{2*-4}=\frac{28}{-8}
=-3+1/2
$