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(14/3)x=28
We move all terms to the left:
(14/3)x-(28)=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+14/3)x-28=0
We multiply parentheses
14x^2-28=0
a = 14; b = 0; c = -28;
Δ = b2-4ac
Δ = 02-4·14·(-28)
Δ = 1568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1568}=\sqrt{784*2}=\sqrt{784}*\sqrt{2}=28\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{2}}{2*14}=\frac{0-28\sqrt{2}}{28} =-\frac{28\sqrt{2}}{28} =-\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{2}}{2*14}=\frac{0+28\sqrt{2}}{28} =\frac{28\sqrt{2}}{28} =\sqrt{2} $
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