(14/9)(a)=a+1400

Solution for (14/9)(a)=a+1400 equation:

(14/9)(a)=a+1400

We move all terms to the left:

(14/9)(a)-(a+1400)=0


Domain of the equation: 9)a!=0

a!=0/1

a!=0

a∈R


We add all the numbers together, and all the variables

(+14/9)a-(a+1400)=0

We multiply parentheses

14a^2-(a+1400)=0

We get rid of parentheses

14a^2-a-1400=0

We add all the numbers together, and all the variables

14a^2-1a-1400=0

a = 14; b = -1; c = -1400;
Δ = b2-4ac
Δ = -12-4·14·(-1400)
Δ = 78401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{78401}}{2*14}=\frac{1-\sqrt{78401}}{28}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{78401}}{2*14}=\frac{1+\sqrt{78401}}{28}
$