(14/x-5)+(3x+2)/x=0

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Solution for (14/x-5)+(3x+2)/x=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x+2)/x+14/x-5 = 0

(3*x+2)/x+14/x+(-5*x)/x = 0

3*x-5*x+2+14 = 0

3*x-5*x+16 = 0

16-2*x = 0

(16-2*x)/x = 0

(16-2*x)/x = 0 // * x

16-2*x = 0

16-2*x = 0 // - 16

-2*x = -16 // : -2

x = -16/(-2)

x = 8

x = 8

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