(14/x-5)+(3x+2/x)=0

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Solution for (14/x-5)+(3x+2/x)=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x+14/x+2/x-5 = 0

3*x^1+16*x^-1-5*x^0 = 0

(3*x^2-5*x^1+16*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2-5*x^1+16*x^0) = 0

x^1

3*x^2-5*x+16 = 0

3*x^2-5*x+16 = 0

DELTA = (-5)^2-(3*4*16)

DELTA = -167

DELTA < 0

x in { } 

x belongs to the empty set

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