(140/2)+12-(4x2)=2

Solution for (140/2)+12-(4x2)=2 equation:

(140/2)+12-(4x^2)=2

We move all terms to the left:

(140/2)+12-(4x^2)-(2)=0

determiningTheFunctionDomain
-4x^2+12-2+(140/2)=0

We add all the numbers together, and all the variables

-4x^2+12-2+70=0

We add all the numbers together, and all the variables

-4x^2+80=0

a = -4; b = 0; c = +80;
Δ = b2-4ac
Δ = 02-4·(-4)·80
Δ = 1280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1280}=\sqrt{256*5}=\sqrt{256}*\sqrt{5}=16\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{5}}{2*-4}=\frac{0-16\sqrt{5}}{-8}
=-\frac{16\sqrt{5}}{-8}
=-\frac{2\sqrt{5}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{5}}{2*-4}=\frac{0+16\sqrt{5}}{-8}
=\frac{16\sqrt{5}}{-8}
=\frac{2\sqrt{5}}{-1}
$