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(14b+5)(11b+15)=0
We multiply parentheses ..
(+154b^2+210b+55b+75)=0
We get rid of parentheses
154b^2+210b+55b+75=0
We add all the numbers together, and all the variables
154b^2+265b+75=0
a = 154; b = 265; c = +75;
Δ = b2-4ac
Δ = 2652-4·154·75
Δ = 24025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{24025}=155$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(265)-155}{2*154}=\frac{-420}{308} =-1+4/11 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(265)+155}{2*154}=\frac{-110}{308} =-5/14 $
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