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(14b+6)(15b+10)=0
We multiply parentheses ..
(+210b^2+140b+90b+60)=0
We get rid of parentheses
210b^2+140b+90b+60=0
We add all the numbers together, and all the variables
210b^2+230b+60=0
a = 210; b = 230; c = +60;
Δ = b2-4ac
Δ = 2302-4·210·60
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(230)-50}{2*210}=\frac{-280}{420} =-2/3 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(230)+50}{2*210}=\frac{-180}{420} =-3/7 $
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