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(14x+3)(4x+10)=157
We move all terms to the left:
(14x+3)(4x+10)-(157)=0
We multiply parentheses ..
(+56x^2+140x+12x+30)-157=0
We get rid of parentheses
56x^2+140x+12x+30-157=0
We add all the numbers together, and all the variables
56x^2+152x-127=0
a = 56; b = 152; c = -127;
Δ = b2-4ac
Δ = 1522-4·56·(-127)
Δ = 51552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{51552}=\sqrt{144*358}=\sqrt{144}*\sqrt{358}=12\sqrt{358}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(152)-12\sqrt{358}}{2*56}=\frac{-152-12\sqrt{358}}{112} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(152)+12\sqrt{358}}{2*56}=\frac{-152+12\sqrt{358}}{112} $
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