(14x+4)(11x+1)=180

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Solution for (14x+4)(11x+1)=180 equation:



(14x+4)(11x+1)=180
We move all terms to the left:
(14x+4)(11x+1)-(180)=0
We multiply parentheses ..
(+154x^2+14x+44x+4)-180=0
We get rid of parentheses
154x^2+14x+44x+4-180=0
We add all the numbers together, and all the variables
154x^2+58x-176=0
a = 154; b = 58; c = -176;
Δ = b2-4ac
Δ = 582-4·154·(-176)
Δ = 111780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{111780}=\sqrt{324*345}=\sqrt{324}*\sqrt{345}=18\sqrt{345}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-18\sqrt{345}}{2*154}=\frac{-58-18\sqrt{345}}{308} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+18\sqrt{345}}{2*154}=\frac{-58+18\sqrt{345}}{308} $

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