(14x+9)(5x-7)=0

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Solution for (14x+9)(5x-7)=0 equation:



(14x+9)(5x-7)=0
We multiply parentheses ..
(+70x^2-98x+45x-63)=0
We get rid of parentheses
70x^2-98x+45x-63=0
We add all the numbers together, and all the variables
70x^2-53x-63=0
a = 70; b = -53; c = -63;
Δ = b2-4ac
Δ = -532-4·70·(-63)
Δ = 20449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20449}=143$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-143}{2*70}=\frac{-90}{140} =-9/14 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+143}{2*70}=\frac{196}{140} =1+2/5 $

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