(14x-28/2x)=(8/7)

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Solution for (14x-28/2x)=(8/7) equation: 



(14x-28/2x)=(8/7)

We move all terms to the left:

(14x-28/2x)-((8/7))=0



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+14x-28/2x)-((+8/7))=0

We get rid of parentheses

14x-28/2x-((+8/7))=0

We calculate fractions


14x+()/14x^2+(-((+8*2x)/14x^2=0

We multiply all the terms by the denominator


14x*14x^2+(-((+8*2x)+()=0



We calculate terms in parentheses: +(-((+8*2x)+(), so:

-((+8*2x)+(



Wy multiply elements

196x^3+(-((+8*2x)+()=0



We calculate terms in parentheses: +(-((+8*2x)+(), so:

-((+8*2x)+(



We do not support expression: x^3

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