(14x2+6x)=(55+13x2)

Solution for (14x2+6x)=(55+13x2) equation:

(14x^2+6x)=(55+13x^2)

We move all terms to the left:

(14x^2+6x)-((55+13x^2))=0

We get rid of parentheses

-((55+13x^2))+14x^2+6x=0


We calculate terms in parentheses: -((55+13x^2)), so:

(55+13x^2)

We get rid of parentheses

13x^2+55

Back to the equation:

-(13x^2+55)


We add all the numbers together, and all the variables

14x^2+6x-(13x^2+55)=0

We get rid of parentheses

14x^2-13x^2+6x-55=0

We add all the numbers together, and all the variables

x^2+6x-55=0

a = 1; b = 6; c = -55;
Δ = b2-4ac
Δ = 62-4·1·(-55)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-16}{2*1}=\frac{-22}{2}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+16}{2*1}=\frac{10}{2}
=5
$