(15)/(5x-5)+(1/5)=(3)/(x-1)

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Solution for (15)/(5x-5)+(1/5)=(3)/(x-1) equation:


D( x )

x-1 = 0

5*x-5 = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

5*x-5 = 0

5*x-5 = 0

5*x-5 = 0 // + 5

5*x = 5 // : 5

x = 5/5

x = 1

x in (-oo:1) U (1:+oo)

15/(5*x-5)+1/5 = 3/(x-1) // - 3/(x-1)

15/(5*x-5)-(3/(x-1))+1/5 = 0

15/(5*x-5)-3*(x-1)^-1+1/5 = 0

15/(5*x-5)-3/(x-1)+1/5 = 0

(5*15*(x-1))/(5*(5*x-5)*(x-1))+(-3*5*(5*x-5))/(5*(5*x-5)*(x-1))+(1*(5*x-5)*(x-1))/(5*(5*x-5)*(x-1)) = 0

5*15*(x-1)-3*5*(5*x-5)+1*(5*x-5)*(x-1) = 0

5*x^2-10*x+5 = 0

5*x^2-10*x+5 = 0

5*(x^2-2*x+1) = 0

x^2-2*x+1 = 0

DELTA = (-2)^2-(1*1*4)

DELTA = 0

x = 2/(1*2)

x = 1 or x = 1

5*(x-1)^2 = 0

(5*(x-1)^2)/(5*(5*x-5)*(x-1)) = 0

(5*(x-1)^2)/(5*(5*x-5)*(x-1)) = 0 // * 5*(5*x-5)*(x-1)

5*(x-1)^2 = 0

x-1 = 0 // + 1

x = 1

x in { 1}

x belongs to the empty set

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