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(15+2x)(20+2x)=336
We move all terms to the left:
(15+2x)(20+2x)-(336)=0
We add all the numbers together, and all the variables
(2x+15)(2x+20)-336=0
We multiply parentheses ..
(+4x^2+40x+30x+300)-336=0
We get rid of parentheses
4x^2+40x+30x+300-336=0
We add all the numbers together, and all the variables
4x^2+70x-36=0
a = 4; b = 70; c = -36;
Δ = b2-4ac
Δ = 702-4·4·(-36)
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5476}=74$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-74}{2*4}=\frac{-144}{8} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+74}{2*4}=\frac{4}{8} =1/2 $
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