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(15+x)(x+15)=231
We move all terms to the left:
(15+x)(x+15)-(231)=0
We add all the numbers together, and all the variables
(x+15)(x+15)-231=0
We multiply parentheses ..
(+x^2+15x+15x+225)-231=0
We get rid of parentheses
x^2+15x+15x+225-231=0
We add all the numbers together, and all the variables
x^2+30x-6=0
a = 1; b = 30; c = -6;
Δ = b2-4ac
Δ = 302-4·1·(-6)
Δ = 924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{924}=\sqrt{4*231}=\sqrt{4}*\sqrt{231}=2\sqrt{231}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{231}}{2*1}=\frac{-30-2\sqrt{231}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{231}}{2*1}=\frac{-30+2\sqrt{231}}{2} $
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