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(15-9x)/(3+x)=0
Domain of the equation: (3+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
(-9x+15)/(x+3)=0
We multiply all the terms by the denominator
(-9x+15)=0
We get rid of parentheses
-9x+15=0
We move all terms containing x to the left, all other terms to the right
-9x=-15
x=-15/-9
x=1+2/3
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