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(150x^2)=(125x^2)
We move all terms to the left:
(150x^2)-((125x^2))=0
determiningTheFunctionDomain 150x^2-125x^2=0
We add all the numbers together, and all the variables
25x^2=0
a = 25; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·25·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{50}=0$
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