(15c+30)=1/3(102-12c)

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Solution for (15c+30)=1/3(102-12c) equation: 


c in (-oo:+oo)

15*c+30 = (1/3)*(102-(12*c)) // - (1/3)*(102-(12*c))

15*c-((1/3)*(102-(12*c)))+30 = 0

(-1/3)*(102-12*c)+15*c+30 = 0

15*c-1/3*(102-12*c)+30 = 0

15*c-1/3*(102-12*c)+30 = 0

19*c-34+30 = 0

19*c-4 = 0

19*c-4 = 0

19*c-4 = 0 // + 4

19*c = 4 // : 19

c = 4/19

c = 4/19

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