(15t)/5=(2t+3)/6

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Solution for (15t)/5=(2t+3)/6 equation: 



(15t)/5=(2t+3)/6

We move all terms to the left:

(15t)/5-((2t+3)/6)=0

We calculate fractions


90t^2/()+(-((2t+3)*5)/()=0



We calculate terms in parentheses: +(-((2t+3)*5)/(), so:

-((2t+3)*5)/(

We multiply all the terms by the denominator


-((2t+3)*5)



We calculate terms in parentheses: -((2t+3)*5), so:

(2t+3)*5

We multiply parentheses

10t+15

Back to the equation:

-(10t+15)



We get rid of parentheses

-10t-15

Back to the equation:

+(-10t-15)



We get rid of parentheses

90t^2/()-10t-15=0

We multiply all the terms by the denominator


90t^2-10t*()-15*()=0

We add all the numbers together, and all the variables

90t^2-10t*()=0

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