(15w-2)(w+5)=72

Solution for (15w-2)(w+5)=72 equation:

(15w-2)(w+5)=72

We move all terms to the left:

(15w-2)(w+5)-(72)=0

We multiply parentheses ..

(+15w^2+75w-2w-10)-72=0

We get rid of parentheses

15w^2+75w-2w-10-72=0

We add all the numbers together, and all the variables

15w^2+73w-82=0

a = 15; b = 73; c = -82;
Δ = b2-4ac
Δ = 732-4·15·(-82)
Δ = 10249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(73)-\sqrt{10249}}{2*15}=\frac{-73-\sqrt{10249}}{30}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(73)+\sqrt{10249}}{2*15}=\frac{-73+\sqrt{10249}}{30}
$