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(15x+1)=(10+12x)
We move all terms to the left:
(15x+1)-((10+12x))=0
We add all the numbers together, and all the variables
(15x+1)-((12x+10))=0
We get rid of parentheses
15x-((12x+10))+1=0
We calculate terms in parentheses: -((12x+10)), so:We get rid of parentheses
(12x+10)
We get rid of parentheses
12x+10
Back to the equation:
-(12x+10)
15x-12x-10+1=0
We add all the numbers together, and all the variables
3x-9=0
We move all terms containing x to the left, all other terms to the right
3x=9
x=9/3
x=3
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