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(15x+30)/(-5x-10)=x
We move all terms to the left:
(15x+30)/(-5x-10)-(x)=0
Domain of the equation: (-5x-10)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-5x!=10
x!=10/-5
x!=-2
x∈R
-1x+(15x+30)/(-5x-10)=0
We multiply all the terms by the denominator
-1x*(-5x-10)+(15x+30)=0
We multiply parentheses
5x^2+10x+(15x+30)=0
We get rid of parentheses
5x^2+10x+15x+30=0
We add all the numbers together, and all the variables
5x^2+25x+30=0
a = 5; b = 25; c = +30;
Δ = b2-4ac
Δ = 252-4·5·30
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5}{2*5}=\frac{-30}{10} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5}{2*5}=\frac{-20}{10} =-2 $
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