(15x+4)+(22x+4)=120

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Solution for (15x+4)+(22x+4)=120 equation:



(15x+4)+(22x+4)=120
We move all terms to the left:
(15x+4)+(22x+4)-(120)=0
We get rid of parentheses
15x+22x+4+4-120=0
We add all the numbers together, and all the variables
37x-112=0
We move all terms containing x to the left, all other terms to the right
37x=112
x=112/37
x=3+1/37

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