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(15x+42)(x+8=9)
We move all terms to the left:
(15x+42)(x+8-(9))=0
We add all the numbers together, and all the variables
(15x+42)(x-1)=0
We multiply parentheses ..
(+15x^2-15x+42x-42)=0
We get rid of parentheses
15x^2-15x+42x-42=0
We add all the numbers together, and all the variables
15x^2+27x-42=0
a = 15; b = 27; c = -42;
Δ = b2-4ac
Δ = 272-4·15·(-42)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3249}=57$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-57}{2*15}=\frac{-84}{30} =-2+4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+57}{2*15}=\frac{30}{30} =1 $
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