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(15x+6)(x-1)=0
We multiply parentheses ..
(+15x^2-15x+6x-6)=0
We get rid of parentheses
15x^2-15x+6x-6=0
We add all the numbers together, and all the variables
15x^2-9x-6=0
a = 15; b = -9; c = -6;
Δ = b2-4ac
Δ = -92-4·15·(-6)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-21}{2*15}=\frac{-12}{30} =-2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+21}{2*15}=\frac{30}{30} =1 $
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