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(15x+9)22x+4=120
We move all terms to the left:
(15x+9)22x+4-(120)=0
We add all the numbers together, and all the variables
(15x+9)22x-116=0
We multiply parentheses
330x^2+198x-116=0
a = 330; b = 198; c = -116;
Δ = b2-4ac
Δ = 1982-4·330·(-116)
Δ = 192324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{192324}=\sqrt{4*48081}=\sqrt{4}*\sqrt{48081}=2\sqrt{48081}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(198)-2\sqrt{48081}}{2*330}=\frac{-198-2\sqrt{48081}}{660} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(198)+2\sqrt{48081}}{2*330}=\frac{-198+2\sqrt{48081}}{660} $
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