(15y+4)(2y+11)=0

Solution for (15y+4)(2y+11)=0 equation:

(15y+4)(2y+11)=0

We multiply parentheses ..

(+30y^2+165y+8y+44)=0

We get rid of parentheses

30y^2+165y+8y+44=0

We add all the numbers together, and all the variables

30y^2+173y+44=0

a = 30; b = 173; c = +44;
Δ = b2-4ac
Δ = 1732-4·30·44
Δ = 24649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24649}=157$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(173)-157}{2*30}=\frac{-330}{60}
=-5+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(173)+157}{2*30}=\frac{-16}{60}
=-4/15
$