(16)/(2b+2)

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Solution for (16)/(2b+2) equation: 


D( b )

2*b+2 = 0

2*b+2 = 0

2*b+2 = 0

2*b+2 = 0 // - 2

2*b = -2 // : 2

b = -2/2

b = -1

b in (-oo:-1) U (-1:+oo)

16/(2*b+2) = 0

b belongs to the empty set

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