(16+2x)(12+2x)=0

Solution for (16+2x)(12+2x)=0 equation:

(16+2x)(12+2x)=0

We add all the numbers together, and all the variables

(2x+16)(2x+12)=0

We multiply parentheses ..

(+4x^2+24x+32x+192)=0

We get rid of parentheses

4x^2+24x+32x+192=0

We add all the numbers together, and all the variables

4x^2+56x+192=0

a = 4; b = 56; c = +192;
Δ = b2-4ac
Δ = 562-4·4·192
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-8}{2*4}=\frac{-64}{8}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+8}{2*4}=\frac{-48}{8}
=-6
$