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(16+2x)(18+2x)=1.472
We move all terms to the left:
(16+2x)(18+2x)-(1.472)=0
We add all the numbers together, and all the variables
(2x+16)(2x+18)-(1.472)=0
We add all the numbers together, and all the variables
(2x+16)(2x+18)-1.472=0
We multiply parentheses ..
(+4x^2+36x+32x+288)-1.472=0
We get rid of parentheses
4x^2+36x+32x+288-1.472=0
We add all the numbers together, and all the variables
4x^2+68x+286.528=0
a = 4; b = 68; c = +286.528;
Δ = b2-4ac
Δ = 682-4·4·286.528
Δ = 39.552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-\sqrt{39.552}}{2*4}=\frac{-68-\sqrt{39.552}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+\sqrt{39.552}}{2*4}=\frac{-68+\sqrt{39.552}}{8} $
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