(16+2x)(20+2x)=320

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Solution for (16+2x)(20+2x)=320 equation: 


Simplifying
(16 + 2x)(20 + 2x) = 320

Multiply (16 + 2x) * (20 + 2x)
(16(20 + 2x) + 2x * (20 + 2x)) = 320
((20 * 16 + 2x * 16) + 2x * (20 + 2x)) = 320
((320 + 32x) + 2x * (20 + 2x)) = 320
(320 + 32x + (20 * 2x + 2x * 2x)) = 320
(320 + 32x + (40x + 4x2)) = 320

Combine like terms: 32x + 40x = 72x
(320 + 72x + 4x2) = 320

Add '-320' to each side of the equation.
320 + 72x + -320 + 4x2 = 320 + -320

Reorder the terms:
320 + -320 + 72x + 4x2 = 320 + -320

Combine like terms: 320 + -320 = 0
0 + 72x + 4x2 = 320 + -320
72x + 4x2 = 320 + -320

Combine like terms: 320 + -320 = 0
72x + 4x2 = 0

Solving
72x + 4x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '4x'.
4x(18 + x) = 0

Ignore the factor 4.

Subproblem 1
Set the factor 'x' equal to zero and attempt to solve:

Simplifying
x = 0

Solving
x = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying
x = 0

Subproblem 2
Set the factor '(18 + x)' equal to zero and attempt to solve:

Simplifying
18 + x = 0

Solving
18 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-18' to each side of the equation.
18 + -18 + x = 0 + -18

Combine like terms: 18 + -18 = 0
0 + x = 0 + -18
x = 0 + -18

Combine like terms: 0 + -18 = -18
x = -18

Simplifying
x = -18
Solution
x = {0, -18}

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